若3^m=6 9^n=2,求3^2m-4n+1的值
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若3^m=69^n=2,求3^2m-4n+1的值若3^m=69^n=2,求3^2m-4n+1的值若3^m=69^n=2,求3^2m-4n+1的值9^n=3^2n=23^(2m-4n+1)=3^2m÷3
若3^m=6 9^n=2,求3^2m-4n+1的值
若3^m=6 9^n=2,求3^2m-4n+1的值
若3^m=6 9^n=2,求3^2m-4n+1的值
9^n=3^2n=2
3^(2m-4n+1)
=3^2m÷3^4nx3
=(3^m)²÷(3^2n)^²x3
=6²÷2²x3
=27
3^m=6
9^n=3^2n=2
3^(2m-4n+1)
=3^2m×3^(-4n)×3
=3(3^m)²÷[(3^2n)×(3^2n)]
=3×6²÷(2×2)
=27
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