求y=x^2-x+1/2x^2-2x+3的值域,
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求y=x^2-x+1/2x^2-2x+3的值域,求y=x^2-x+1/2x^2-2x+3的值域,求y=x^2-x+1/2x^2-2x+3的值域,y=1/2*[(2x²-2x+3)-1]/(2
求y=x^2-x+1/2x^2-2x+3的值域,
求y=x^2-x+1/2x^2-2x+3的值域,
求y=x^2-x+1/2x^2-2x+3的值域,
y=1/2*[(2x²-2x+3)-1]/(2x²-2x+3)
=1/2*[1-1/(2x²-2x+3)]
而2x²-2x+3=2(x-1/2)²+5/2≥5/2
所以0
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