函数f(x)=2sin(2x+π/3)-1 1求f(x)的最小正周期 2求f(x)的值域 需要过函数f(x)=2sin(2x+π/3)-1 1求f(x)的最小正周期 2求f(x)的值域

已知函数f(x)=2根号3sin平方x-sin（2x-π/3) 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+a) -π 设函数f(x)=sin(2x+ φ)(-π 函数f(x)=sin(2x+&）(-π 函数f(x)=sin(2x+t) (-π 函数f(x)=sin(2x+a）(-π 设函数f(x)=sin(2x+φ)(-π