求 lim n→∞ ∫[1,0]x^n*dx/(1+x^(1/2)+x) 说是按定积分的定义或性质求,怎么求呢?

求极限lim(x→∞)（1/n+2/n+3/n..+n/n） 求极限(1)lim(n->∞)∫(0,1)x^n/(1+x)dx (2)lim(n->∞)∫(n+k,n)sinx/xdx (k>0) 求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞) 求 lim n→∞∫(上限1下限0)x^n/(1＋x^2)dx lim[n→∞] (x^n+1)^(1/n) 求lim n→∞ (1+2/n)^n+3 求 lim (n→+∞) n^( 1/n)的极限 lim(arctan n)^1/n (n→∞)求极值 求极限 x→∞lim(3^n+1)/(3^(n+1)+2^n)= 求下列两个极限lim（x→∞）e^(-x^2)*∫(0→x)[t^2*e^(t^2)]dt / xlim(n→∞)[(1+1/n)(1+2/n)...(1+n/n)]^(1/n) lim(n→∞)∫(0→1)x^n/(x+1)dx lim(cos1/n)^n^2 n->∞lim (1+|x|)^1/x x->0 求极限,lim(x->0) (1-2sinx)^(3/x)lim(n->+∞) (n!-4^n) / (6+ln(n)+n^2) 从lim(n→∞) (1/n)[1/(3 + 1/n) + 1/(3 + 2/n) + ...+ 1/(3 + n/n)] 怎么变为∫(0→1) dx/(3 + x) 1.6求极限lim(x→∞) [1+2+3+......+(n-1)]/ n^21.6求极限lim(x→∞) [1+2+3+......+(n-1)]/ n^2 设f(x)是可导函数且f(0)=0,F(x)=∫t^(n-1)f(x^n-t^n)dt,求lim(x→+∞)F(x)/x^2n设f(x)是可导函数,且f(0)=0,F(x)=∫t^(n-1)f(x^n-t^n)dt,求lim(x→+∞)F(x)/x^2n答案是f'(0)/2n求详解 求 lim n→∞ ∫[1,0]x^n*dx/(1+x^(1/2)+x) 说是按定积分的定义或性质求,怎么求呢? lim ∫1 x∧n╱1＋xdx＝0 n→∞ 0