因式分解(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1)使用换元法帅哥,为什么你不回答我的问题了?
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因式分解(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1)使用换元法帅哥,为什么你不回答我的问题了?
因式分解(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1)使用换元法
帅哥,为什么你不回答我的问题了?
因式分解(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1)使用换元法帅哥,为什么你不回答我的问题了?
您好,土豆实力团为您答疑解难.
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答题不易,请谅解,谢谢.
另祝您学习进步!
为什么我看成了师哥…………
(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1)
=(x^2+y^2-2x+1)^2-4y(1-x)(x^2-y^2-2x+1)
=[(x-1)^2+y^2]^2+4y(x-1)[(x-1)^2-y^2]
=[(x-1)^2+y^2]^2+4y(x-1)[(x-1)^2+y^2-2y^2]
=[(x-1)^2+y^2]^2+2*2y(x...
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(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1)
=(x^2+y^2-2x+1)^2-4y(1-x)(x^2-y^2-2x+1)
=[(x-1)^2+y^2]^2+4y(x-1)[(x-1)^2-y^2]
=[(x-1)^2+y^2]^2+4y(x-1)[(x-1)^2+y^2-2y^2]
=[(x-1)^2+y^2]^2+2*2y(x-1)[(x-1)^2+y^2]+4y^2(x-1)^2
-4y^2(x-1)^2-8y^3(x-1)
=[(x-1)^2+y^2+2y(x-1)]^2-4y^2(x-1)(x-1+2y)
=[(x-1)(x-1+2y)+y^2]^2-4y^2(x-1)(x-1+2y)
=[(x-1)(x-1+2y)]^2+2y^2(x-1)(x-1+2y)+y^4--4y^2(x-1)(x-1+2y)
=[(x-1)(x-1+2y)]^2-2y^2(x-1)(x-1+2y)+y^4
=[(x-1)(x-1+2y)+y^2]^2
=[(x-1)^2+2y(x-1)+y^2]^2
={[(x-1)+y]^2}^2
=(x+y-1)^4
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