化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)要过程!急要!
来源:学生作业帮助网 编辑:六六作业网 时间:2024/09/08 00:49:04
化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)要过程!急要!化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^
化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)要过程!急要!
化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)
要过程!急要!
化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)要过程!急要!
sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)
=(-sinα)^2*(-cosα)*cot(-α)/(-tanα)cos^3(-α+π)
=(sinα)^2*cosα*cotα/tanαcos^3(-α)
=sinα*cosα*cosα/tanα(cosα)^3
=sinα*(cosα)^2/sinα(cosα)^2
=1
化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简!
若cosα>sinα,(-π/2
化简[sin(π/2-α)cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α)
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π)
化简:2sin(π+α)cos(π-α)
化简cos(3/2π+π)sin(-π+α)
化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)]
化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α)
化简:[ cos(α-π/2)/sin(5π/2+α) ] ×sin(α-2π) × cos(2π-α)RT.
化简:[1+2sin(α+2π)*cos(α-2π)]/[sin(α+4π)+cos(α+8π)]
化简sin(α-3/2π)cos(α-π)-sin(α-2π)cos(α-π/2)=?
化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
化简[sin(2π-α)cos(π+α)cos(π/2+α)cos(11π/2-α)]/[cos(π-α)sin(π+α)sin(-π-α)sin[(...化简[sin(2π-α)cos(π+α)cos(π/2+α)cos(11π/2-α)]/[cos(π-α)sin(π+α)sin(-π-α)sin[(9π/2)+α]]