化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
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化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)化简sin^4x+sin^2xcos^2x+cos^2x
化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
x就不写了,原式等于
sin^2(sin^2+cos^2)+cos^2 = sin^2*(1)+cos^2 = sin^2+cos^2 = 1
sin^4x表示(sinx)^4还是(sin4x)^2??
sin^8X+cos^8X+4sin^2Xcos^2x-2sin^4xcos^4X(化简)
化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x
化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
化简cos^4x+sin^2xcos^2x+sin^2x
化简(sin^4+cos^4+sin^2xcos^2x)/(2-sin2x)
∫1/(sin^2xcos^2x)
sin^2xcos^2x不定积分
sin^2xcos^3x的不定积分,
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
求证sin^4x+cos^4x=1-2sin^2xcos^2x
sin^4x+cos^4x=1-2sin^2Xcos^2X谢谢额
化简:cos^4x+sin^2xcos^2x+cos^2x
sin^4+sin^2xcos^2x+cos^2x 证明 =1
积分 sin^4xcos^2x dx利用三角学解以下积分(如图)Hints:sin^4xcos^2x = sin^2x(sinxcosx)^2
sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos^2x+cos^4x 是根据什么化简的?
化简sin^2x+sin^2y-sin^2xsin^2y+cos^2xcos^2y
1-2sin xcos x/cos的平方x
求证 cos*xcos*y + sin*xsin*y + sin*xcos*y + xin*ycos*x = 1cos*xcos*y + sin*xsin*y + sin*xcos*y + sin*ycos*x = 1注意:[*] 的意思是 [ ^2 ]写下左右过程..