(3x^2-2x+1)(3x^2-2x-7)+12=0RT解方程啊

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 13:49:51
(3x^2-2x+1)(3x^2-2x-7)+12=0RT解方程啊(3x^2-2x+1)(3x^2-2x-7)+12=0RT解方程啊(3x^2-2x+1)(3x^2-2x-7)+12=0RT解方程啊由

(3x^2-2x+1)(3x^2-2x-7)+12=0RT解方程啊
(3x^2-2x+1)(3x^2-2x-7)+12=0
RT
解方程啊

(3x^2-2x+1)(3x^2-2x-7)+12=0RT解方程啊
由(3x^2-2x+1)(3x^2-2x-7)+12=0得(3x^2-2x+1)(3x^2-2x+1-8)+12=0
有(3x^2-2x+1)^2-8(3x^2-2x+1)+12=0
即(3x^2-2x+1-6)(3x^2-2x+1-2)=0
即有3x^2-2x-5=0或者3x^2-2x-1=0,可解得x=5/3或x=-1或x=-1/3或x=1
经检验,所有根均为原方程的解, 故可得x=5/3或x=-1或x=-1/3或x=1

1 -1/3 -1 5/3