计算2^log(1/4)3=?(1/4是底数,3是真数）求计算过程,谢谢!

(log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题. 计算：（1） log(2)(3)*log(3)(4)*log(4)(5)（2）log(2)(7)*log(√7)(8) 计算：1/[log(2)3]+1/[log(5)3]=? 求大神指点,lingo出现错误代码11,这是为什么?model:!目标函数;min=(0.005*((@log(1+k))^2+(@log(1+2*k))^2+(@log(1+3*k))^2+(@log(1+4*k))^2+(@log(1+5*k))^2))!/(@log(1+k)+@log(1+2*k)+@log(1+3*k)+@log(1+4*k)+@log(1+5*k));!约束条件;(@log 对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(2)(3)} X {log(3)(4)+log(9)(2)}3.(lg2)^+1g2X 1g5 +1g50 计算2^log(1/4)3=?(1/4是底数,3是真数）求计算过程,谢谢! [log(4)3+log(8)3][log(3)2+log(9)2]-log(1/2)32∧1/4过程详细点,log(4)3是log以4为底3的对数， 计算：8^(1-log(83))(27^(2/3))-log(32) 计算1.2log以5为底10+log以5为底0.25 2.已知lg2=0.3010,lg3=0.4771,求lg根号下45 3.【（1-log以6为底3）²+log以6为底2*log以6为底18】*log以4为底6 (iog(4)3+log(8)3)(log(3)2+log(9)8)怎样计算 化简:1/log(3)x 1/log(4)x 1/log(5)x=……(答案是1/log(60)x 如何计算啊.（log底数4真数3+log底数8真数3）乘（log底数3真数2+log底数9真数2）=? 设a=log(1/3)1/2 b=log(1/3)2/3 c=log(3)4/3 则abc的大小 关系是? 化简2log`5(10)+log`3(0.25）+log`1/5(125)=(2) log`2(根号2）+log`9(27）+（1/4)^log`4(1/16) 注意 `为下角标 log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y [log(3)3^1/2]^2+log(0.25)1/4+9log5根号5-log（根号3）1=? 1/log（2）x+1/log（3）x+1/log（4）x=1,x=? 2^log(4)(3)加3^log(9)(1/4)加5^log(1/25)(2)