若x+y=-2,求2x+3y-3xy+(4xy-3x)-(4y-7)的值.
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若x+y=-2,求2x+3y-3xy+(4xy-3x)-(4y-7)的值.若x+y=-2,求2x+3y-3xy+(4xy-3x)-(4y-7)的值.若x+y=-2,求2x+3y-3xy+(4xy-3x
若x+y=-2,求2x+3y-3xy+(4xy-3x)-(4y-7)的值.
若x+y=-2,求2x+3y-3xy+(4xy-3x)-(4y-7)的值.
若x+y=-2,求2x+3y-3xy+(4xy-3x)-(4y-7)的值.
2x+3y-3xy+(4xy-3x)-(4y-7)
=2x+3y-3xy+4xy-3x-4y+7
=-x-y+xy+7
∵x+y=-2
所以
原式=2+xy+7
=xy+9
原题中一定给出了xy的值,不然算不了.
2x+3y-3xy+(4xy-3x)-(4y-7)
=2x+3y-3xy+4xy-3x-4y+7
=(2x-3x)+(3y-4y)-(3xy-4xy)+7
=(-x)+(-y)-(-xy)+7
=-x-y+xy+7
=-(x+y)+xy+7
已知:x+y=-2
=-(-2)+xy+7
=9+xy
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