若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/22 19:02:31
若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy
若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值
若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值
若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值
x+y=5xy
（2x-3xy+2y)/(x+2xy+y）
=[2（x+y）-3xy]/[(x+y)+2xy]
=(2×5xy-3xy)/(5xy+2xy)
=7xy/7xy
=1
若x+y-5xy=0则x+y=5xy
(2x-3xy+2y)/(x+2xy+y)
=（2X+2Y-3XY）/(X+Y+2XY)
=（2X+2Y）-3XY/（X+Y）+2XY
=2（X+Y）-3XY/（X+Y）+2XY
=2×5XY-3XY/5XY+2XY
=10XY-3XY/7XY
=7XY/7XY
=1