﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013

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﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013﹙0.22-0.2065﹚÷﹙3.6×0.0

﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013
﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013

﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013
﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013
=0.0135/0.054分之2.5
=0.25分之2.5
=2.5/0.25
=10

=[(352/10000)÷(13/1000)]/(1/4)
=[(352/10000)*(1000/13)]/(1/4)
=(5/2)/(1/4)
=(5/2)*4
=10

﹙0.22-0.2065﹚÷﹙3.6×0.015﹚分之0.0325÷0.013 计算,﹙n/m﹚ √ ﹙n/2m²﹚ × [ ﹙-1/m﹚ √ ﹙n³/m³﹚ ] ÷ √ ﹙n/2m³﹚﹙m>0,n>0﹚ ﹙﹣7﹚×﹙﹣5﹚-90÷﹙﹣15﹚ ( )×9-4×﹙2×﹙ ﹚+3=﹙﹙ ﹚+4﹚÷3 0.0325÷0.013/(0.22-0.2065)÷(3.6×0.015) 等于多少? 2·4-﹙-5分之3﹚+﹙-3·1﹚+5分之4、﹙0·1﹚÷2分之1+﹙-100﹚谢谢啦,我要搞懂, 数学题在线解答-32÷﹙12÷5﹚-﹙1÷7﹚×﹙﹣56﹚÷﹙12÷5﹚ 化简[﹙2000²+1998﹚÷﹙1998²-2000﹚]×[﹙1997²-1997﹚÷﹙1998×2001-4﹚] x-﹙26-x﹚=﹙26-x﹚x÷4 -3²+﹙-2﹚³-﹙0.1﹚²×﹙-10﹚³ ﹙-36 12/29﹚÷12 (1)(√3)/(2)-(1)/(√3-1)+﹙-√2﹚^0+﹙2-√3﹚^-1;(2)﹙√3+1﹚﹙√3-1﹚+﹙√3-1﹚^0-﹙-﹙1/3﹚﹚^-2;(3)﹙1/3﹚^-1+16÷﹙-2﹚^3+﹙2006-(π/5)﹚^0-3;(4)﹙1/3 -66×4-(-2.5)÷(-0.1)﹙-0.02)×﹙-20﹚×﹙-5﹚×4.5 计算﹙xy-x²﹚÷[﹙x-y﹚/xy] 谁会解答﹙112233-112.233﹚÷﹙224466-224.466﹚这道题,奥术计算题 计算﹙-x﹚³÷﹙-x﹚²的结果是 ﹙x²-4x-21﹚÷﹙x﹢3﹚ ﹙m²-4n²﹚÷﹙2n-m﹚= 已知函数fx是定义在R上的奇函数,且对任意 x1,x2恒有fx1-fx2÷x1-x2>0,则 A f﹙3﹚>f﹙-5﹚  B f﹙-3﹚>f ﹙-5﹚  C f﹙-5﹚>f﹙3﹚  Df﹙-5﹚<f﹙-3﹚    求答案,B和D一样