(2m+n-p)(2m-n+p)==?

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(2m+n-p)(2m-n+p)==?(2m+n-p)(2m-n+p)==?(2m+n-p)(2m-n+p)==?原式=[2m+(n-p)][2m-(n-p)]=(2m)²-(n-p)&su

(2m+n-p)(2m-n+p)==?
(2m+n-p)(2m-n+p)==?

(2m+n-p)(2m-n+p)==?
原式=[2m+(n-p)][2m-(n-p)]
=(2m)²-(n-p)²
=4m²-(n²-2pn+p²)
=4m²-n²+2pn-p²

=[2m+(n-p)][2m-(n-p)]
=4m^2-(n-p)^2