已知log7[log3(log2 x)]=0,求x^(-1/2)

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已知log7[log3(log2x)]=0,求x^(-1/2)已知log7[log3(log2x)]=0,求x^(-1/2)已知log7[log3(log2x)]=0,求x^(-1/2)log7[lo

已知log7[log3(log2 x)]=0,求x^(-1/2)
已知log7[log3(log2 x)]=0,求x^(-1/2)

已知log7[log3(log2 x)]=0,求x^(-1/2)
log7[log3(log2x)]=0
所以log3(log2x)=1
所以log2x=3
所以x=8

因为log7[log3(log2x)]=0,所以log3(log2x)=1,即log(2)(x)=3,2^3=8, 最后求的x=8

log7[log3(log2 x)]=0
=>log3(log2 x)=1
=>log2x=3
=>2^3=x
=>x^(-1/2)=2^(-3/2)