log2^(log3^x)=log3^(log4^y)=0则x+y=
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log2^(log3^x)=log3^(log4^y)=0则x+y=log2^(log3^x)=log3^(log4^y)=0则x+y=log2^(log3^x)=log3^(log4^y)=0则x+
log2^(log3^x)=log3^(log4^y)=0则x+y=
log2^(log3^x)=log3^(log4^y)=0则x+y=
log2^(log3^x)=log3^(log4^y)=0则x+y=
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好像弄错了,log2^(log3^x)中2是底数吧?如果是这样应该这么算：
log2^(log3^x)=0,则log3^x=1,x=3
log3^(log4^y)=0,则log4^y=1,y=4
x+y=7
log2(3)+log3(5)+log3(2)=?
log2[log3[log5 125]]=?log2[log3[log5 125]]=?
(log2 6)×(log3 6)-(log2 3+log3 2)=
(log2 6)×(log3 6)-(log2 3+log3 2)=
log5[log2(log9/log3)]=?
log2(3)*log3(2)=?
(log3^2)(log2^3)=
“log6=log2+log3么?”
log2(log3(log4x)=0
log2^(log3^x)=log3^(log4^y)=0则x+y=
已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y
已知log2(log3(log4x))=log3(log4(log2y))=0,求x+y的值
已知:log2[log3(log4x)]=log3[log4（log2y)]=0 求x+y的值
log2[log3(log4x)]=log3[log4(log2y)]=0求x+y的值,
log5[log3(log2^x)]=1,x=
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已知log2(log3 x)=1,求x