因式分解x2+y2-xy-x-y+1
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因式分解x2+y2-xy-x-y+1因式分解x2+y2-xy-x-y+1因式分解x2+y2-xy-x-y+1x2+y2-xy-x-y+1=1/2(2x2+2y2-2xy-2x-2y+2)=1/2(x2
因式分解x2+y2-xy-x-y+1
因式分解x2+y2-xy-x-y+1
因式分解x2+y2-xy-x-y+1
x2+y2-xy-x-y+1=1/2(2x2+2y2-2xy-2x-2y+2)=1/2(x2-2xy+y2+x2-2x+1+y2-2y+1)=1/2(x-y)2+1/2(x-1)2+1/2(y-1)2
=2(x+y)-xy-(x+y)+1=(2-1)(x+y)-xy+1=x+y-xy+1
这个题目是这个样子的吗???
我有疑问啊
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