若tana=3 tan(a-b)=4/3,则tanb=
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若tana=3tan(a-b)=4/3,则tanb=若tana=3tan(a-b)=4/3,则tanb=若tana=3tan(a-b)=4/3,则tanb=tanb=tan[a-(a-b)]=[tan
若tana=3 tan(a-b)=4/3,则tanb=
若tana=3 tan(a-b)=4/3,则tanb=
若tana=3 tan(a-b)=4/3,则tanb=
tanb=tan[a-(a-b)]
=[tana-tan(a-b)]/[1+tana*tan(a-b)]
=[3-(4/3)]/(4+1)
=(5/3)/5
=1/3
tan(a-b)=(tana-tanb)/1+tanatanb=(3-4/3)/1+3*4/3=1/3
tan(a+45)?tana=3/4
若tana=3 tan(a-b)=4/3,则tanb=
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tana=3/4,tan(4/∏－a)等于?