已知α是第二象限的角,f(α)=sin(π-α)tan(-α-π)/sin(π+α)cos(2π-α)tan(-α) (1)化简f(α)(2)若sin(α-3π/2)=-1/3,求f(α)的值

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已知α是第二象限的角,f(α)=sin(π-α)tan(-α-π)/sin(π+α)cos(2π-α)tan(-α)(1)化简f(α)(2)若sin(α-3π/2)=-1/3,求f(α)的值已知α是第

已知α是第二象限的角,f(α)=sin(π-α)tan(-α-π)/sin(π+α)cos(2π-α)tan(-α) (1)化简f(α)(2)若sin(α-3π/2)=-1/3,求f(α)的值
已知α是第二象限的角,f(α)=sin(π-α)tan(-α-π)/sin(π+α)cos(2π-α)tan(-α)
(1)化简f(α)
(2)若sin(α-3π/2)=-1/3,求f(α)的值

已知α是第二象限的角,f(α)=sin(π-α)tan(-α-π)/sin(π+α)cos(2π-α)tan(-α) (1)化简f(α)(2)若sin(α-3π/2)=-1/3,求f(α)的值
f(α)=sin(π-α)tan(-α-π)/sin(π+α)cos(2π-α)tan(-α)
=sinα(-tanα)/(-sinα)cosα(-tanα)
=-1/cosα=-secα
(2)若sin(α-3π/2)=-1/3,求f(α)的值
sin(α-3π/2)=-sin(3π/2-α)=cosα=-1/3
f(α)=-1/cosα=3

(1).f(a)=-1\cosa
(2).f(a)=-3

f(a)=[(sina)(-tana)]/[(-sina)(cosa)(-tana)]
f(a)=-1/cosa

sin(a-3π/2)=-sn(3π/2-a)=cosa=-1/3
则:f(a)=-1/cosa=3