求值: sin14π/3+ cos(﹣25π/4)=?
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求值:sin14π/3+cos(﹣25π/4)=?求值:sin14π/3+cos(﹣25π/4)=?求值:sin14π/3+cos(﹣25π/4)=?sin14π/3+cos(-25π/4)=sin(
求值: sin14π/3+ cos(﹣25π/4)=?
求值: sin14π/3+ cos(﹣25π/4)=?
求值: sin14π/3+ cos(﹣25π/4)=?
sin14π/3+cos(-25π/4)= sin(4π+2π/3)+cos(6π+π/4)= sin2π/3+cosπ/4=(根号3+根号2)/2
故答案为:(根号3+根号2)/2
求值: sin14π/3+ cos(﹣25π/4)=?
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