已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1 的值

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/15 07:34:33
已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1的值已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1的值已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1

已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1 的值
已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1 的值

已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1 的值
原式=(y+1)/(x+1)+(x+1)/(y+1)
=[(y+1)²+(x+1)²]/[(x+1)(y+1)]
=[x²+y²+2x+2y+2]/[x+y+xy+1]
=[(x+y)²-2xy+2(x+y)+2]/[(x+y)+(xy)+1]
=[16-24+8+2]/[-4-12+1]
=-2/15

y+1/x+1+x+1/y+1
=[(y+1)²+(x+1)²]/[(x+1)(y+1)]
=[x²+y²+2(x+y)+2]/(x+y+xy+1)
=[(x+y)²+2(x+y)-2xy+2]/(x+y+xy+1)
=[(-4)²+2x(-4)-2x(-12)+2]/(-4-12+1)=-34/15

y+1/x+1+x+1/y+1
=(y+1)²+(x+1)²/(x+1)(y+1)
=y²+2y+1+x²+2x+1/xy+x+y+1
=(x+y)²+2(x+y)+2-2xy/xy+x+y+1
把x+y=-4 xy=-12 代入上式
解得:y+1/x+1+x+1/y+1= ﹣34/15
采纳吧 亲 这么晚写滴 挺辛苦哦