已知x+y=6,xy=-3,则x2y+xy2=

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已知x+y=6,xy=-3,则x2y+xy2=已知x+y=6,xy=-3,则x2y+xy2=已知x+y=6,xy=-3,则x2y+xy2=解x²y+xy²=xy(x+y)=-3×6

已知x+y=6,xy=-3,则x2y+xy2=
已知x+y=6,xy=-3,则x2y+xy2=

已知x+y=6,xy=-3,则x2y+xy2=

x²y+xy²
=xy(x+y)
=-3×6
=-18

x+y=6,xy=-3,
x2y+xy2=xy(x+y)=-3×6=-18

x2y+xy2=xy(x+y)=-3 X 6=-18