lim x->2^(1/2) [1+arcsin(x/2)^2]^(1/2) 极限怎么求
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/24 20:32:57
limx->2^(1/2)[1+arcsin(x/2)^2]^(1/2)极限怎么求limx->2^(1/2)[1+arcsin(x/2)^2]^(1/2)极限怎么求limx->2^(1/2)[1+ar
lim x->2^(1/2) [1+arcsin(x/2)^2]^(1/2) 极限怎么求
lim x->2^(1/2) [1+arcsin(x/2)^2]^(1/2) 极限怎么求
lim x->2^(1/2) [1+arcsin(x/2)^2]^(1/2) 极限怎么求
直接代入就可以了
lim x->2^(1/2) [1+arcsin(x/2)^2]^(1/2)
=(1+π/6)^(1/2)
lim(1-x)^(2/x) x->0
极限:lim(x->2)1/(x-2)
lim(1-(5/x))^x-2
lim(x+e^2x)^(1/sinx)
X趋于0 Lim(xlnx)=Lim(lnx/(1/x))=Lim(1/x/(-1/x^2))=Lim(-x)=0Lim(lnx/(1/x))=Lim(1/x/(-1/x^2))其中这步使怎么转化的?
(1) lim(x->正无穷) x-lnx (2) lim(x->0+) cosx^1/x^2
lim (e^x-sinx-1)/(arcsinx^2)
lim 1/(x-2). 存在极限吗?
lim(x->0)(2xsinx)/(secx-1)
lim(x^2+1/x^2-2x)^x=?
Lim(x>1) x-1/x^2+x-2.计算
lim x→1 x-1/x^2-x
lim(x->无穷大){(2^x-3^x)/2}^(1/x)
Lim [x^2/(x^2-1)]^x (x→∞)
lim x->正无穷大 x ( sqrt(x^2+1)-x )
lim(x->0)((2-x)/(3-x))^1/x
lim(1+x/x)2x (x→∞)
lim(x→0)e^x-x-1/x^2