设f(x)={sinπx(x

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设f(x)={sinπx(x设f(x)={sinπx(x设f(x)={sinπx(xg(1/4)=cos（π/4）f(1/3)=f(-2/3)+1=sin(-2π/3)+1=1-sin(2π/3)g(

设f(x)={sinπx(x
设f(x)={sinπx(x

设f(x)={sinπx(x
g(1/4)=cos（π/4）
f(1/3)=f(-2/3)+1=sin(-2π/3)+1=1-sin(2π/3)
g(5/6)=g(-1/6)-1=cos(-π/6)-1=cos(π/6)-1
f(3/4)=f(-1/4)+1=sin(-π/4)+1
所以g(1/4)+f(1/3)+g(5/6)+f(3/4)=cos（π/4）+1-sin(2π/3)+cos(π/6)-1+sin(-π/4)+1
=1

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