已知a+b/ab=5,求2a-3ab+2b/a+2ab+b值,/号是除号

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已知a+b/ab=5,求2a-3ab+2b/a+2ab+b值,/号是除号已知a+b/ab=5,求2a-3ab+2b/a+2ab+b值,/号是除号已知a+b/ab=5,求2a-3ab+2b/a+2ab+

已知a+b/ab=5,求2a-3ab+2b/a+2ab+b值,/号是除号
已知a+b/ab=5,求2a-3ab+2b/a+2ab+b值,/号是除号

已知a+b/ab=5,求2a-3ab+2b/a+2ab+b值,/号是除号
这道题有两种思路:
(1)由a+b/ab=5得a+b=5ab,
2a-3ab+2b/a+2ab+b得2(a+b)-3ab/(a+b)+2ab=10ab-3ab /5ab+2ab=1
(2) 由a+b/ab=5,
将2a-3ab+2b/a+2ab+b分子分母都除以ab得
(2/b+2/a-3 )/(1/b+1/a+2)= (2a+2b)/ab -3 / (a+b)/ab +2 =(2*5 -3)/(5+2)=1

a+b/ab=5 可得:a+b=5ab
(2a-3ab+2b)/(a+2ab+b)
=[2(a+b)-3ab]/[(a+b)+2ab]
=(10ab-3ab)/(5ab+2ab)
=7ab/7ab
=1

a+b/ab=5
a+b=5ab
2a-3ab+2b/a+2ab+b
=2(a+b)-3ab/[(a+b)+2ab]
=7ab/7ab
=1

因为a+b/ab=5
所以a+b=5ab
则2a-3ab+2b/a+2ab+b
=2(a+b)-3ab/[(a+b)+2ab]
=7ab/7ab
=1
故:“2a-3ab+2b/a+2ab+b”的值为1