24,12,6,3,( ),1 A.0 B.-1 C.2 D.-224,12,6,3,( ),1 A.0 B.-1 C.2 D-2请将解题步骤也写上
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24,12,6,3,(),1A.0B.-1C.2D.-224,12,6,3,(),1A.0B.-1C.2D-2请将解题步骤也写上24,12,6,3,(),1A.0B.-1C.2D.-224,12,6,
24,12,6,3,( ),1 A.0 B.-1 C.2 D.-224,12,6,3,( ),1 A.0 B.-1 C.2 D-2请将解题步骤也写上
24,12,6,3,( ),1 A.0 B.-1 C.2 D.-2
24,12,6,3,( ),1 A.0 B.-1 C.2 D-2请将解题步骤也写上
24,12,6,3,( ),1 A.0 B.-1 C.2 D.-224,12,6,3,( ),1 A.0 B.-1 C.2 D-2请将解题步骤也写上
答案是C1+2=31+2+3=61+2+3+6=121+2+3+6+12=24
化简3a×a×a+12a×a-6a-12 a=根号7-1
因式分解:a^12+a^9+a^6+a^3+1
逻辑运算中A表示什么 (1) 0 · A = 0 (10) 1' = 0; 0' = 1 (2) 1 · A = A (11) 1 + A = 1 (3) A · A = A (12) 0 + A = A (4) A · A' = 0 (13) A + A = A (5) A · B = B · A (14) A + A' = 1 (6) A·(B·C) = (A·B)·C (15) A
逻辑运算中的A表示什么 (1) 0 · A = 0 (10) 1' = 0; 0' = 1 (2) 1 · A = A (11) 1 + A = 1 (3) A · A = A (12) 0 + A = A (4) A · A' = 0 (13) A + A = A (5) A · B = B · A (14) A + A' = 1 (6) A·(B·C) = (A·B)·C (15
已知a^2+a+1=0,求1+a+a^2+a^3+a^4+a^5+a^6+a^7+a^8的值
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(3a+5)-{9a-[6a+2-(12a-10)+2(a+1)]}
(3a+5)-{9a-[6a+2-(12a-10)+2(a+1)]
若a^2+a+1=0,求a+a^2+a^3+a^4+a^5+a^6+……+a^2013得值
若a^2+a+1=0,求a+a^2+a^3+a^4+a^5+a^6+…+a^2013的值
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3/(a+1)-12/(a²-1)-6/(1-a)
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