(x+2y+5)^2+|2x-y-3|=0则x=
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(x+2y+5)^2+|2x-y-3|=0则x=(x+2y+5)^2+|2x-y-3|=0则x=(x+2y+5)^2+|2x-y-3|=0则x=∵﹙x+2y+5﹚²≥0|2x‐y‐3|≥0又
(x+2y+5)^2+|2x-y-3|=0则x=
(x+2y+5)^2+|2x-y-3|=0则x=
(x+2y+5)^2+|2x-y-3|=0则x=
∵﹙x+2y+5﹚²≥0
|2x‐y‐3|≥0
又:﹙x+2y+5﹚²+|2x-y-3|=0
∴ x+2y+5=0
2x-y-3=0
解得:x=1/5
y=﹣13/5.
解:
依题意
x+2y+5=0①
2x-y-3=0②
①+2②=5x-1=0
所以x=1/5
X+2Y+5=0 且 2X-Y-3=0
所以X=1/5 Y=13/5
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