已知x/y=2/3求[5y^2/(x-2y)-x-2y]÷(x^2-6xy+9y^2)/(x-2y)的值

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/16 16:43:45
已知x/y=2/3求[5y^2/(x-2y)-x-2y]÷(x^2-6xy+9y^2)/(x-2y)的值已知x/y=2/3求[5y^2/(x-2y)-x-2y]÷(x^2-6xy+9y^2)/(x-2

已知x/y=2/3求[5y^2/(x-2y)-x-2y]÷(x^2-6xy+9y^2)/(x-2y)的值
已知x/y=2/3求[5y^2/(x-2y)-x-2y]÷(x^2-6xy+9y^2)/(x-2y)的值

已知x/y=2/3求[5y^2/(x-2y)-x-2y]÷(x^2-6xy+9y^2)/(x-2y)的值
x/y=2/3
所以y=3x/2
原式=[5y²-(x-2y)(x+2y)]/(x-2y)÷(x-3y)²/(x-2y)
=(9y²-x²)/(x-2y)*(x-2y)/(x-3y)²
=-(x+3y)(x-3y)/(x-2y)*(x-2y)/(x-3y)²
=-(x+3y)/(x-3y)
=-(x+3x/2)/(x-3x/2)
=5