若x^2+y^2-4x-10y+29=0求分式10y/x-10/y的值
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/23 11:34:52
若x^2+y^2-4x-10y+29=0求分式10y/x-10/y的值若x^2+y^2-4x-10y+29=0求分式10y/x-10/y的值若x^2+y^2-4x-10y+29=0求分式10y/x-1
若x^2+y^2-4x-10y+29=0求分式10y/x-10/y的值
若x^2+y^2-4x-10y+29=0求分式10y/x-10/y的值
若x^2+y^2-4x-10y+29=0求分式10y/x-10/y的值
x^2+y^2-4x-10y+29=0
(x-2)^2+(y-5)^2=0
所以x=2且y=5
所以10y/x-10/y=10*5/2-10/5=23
x²+y²-4x-10y+29=0
x²-4x+4+y²-10y+25=0
(x-2)²+(y-5)²=0
x=2
y=5
50/2-10/5=25-2=23
若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
若x.y满足x^2+4x+y^2-10y+29=0.求x+y的值
若x.y满足条件2x+y-12=0,x-4y+10
已知x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
已知X^2-4X+Y^2-10Y+29=0,求X^2Y^2+2X^3Y^2+X^4Y^2
已知x^2-4x+29-10y+y^2=0,求x^2y^2+2x^3y^2+x^4y^2
{4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
x*x+2x+y*y-4y+5=0 x= y=
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^2+y^2/y)^2的值
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
RT,若(√2x-y)+y^2+4y+4=0,求[(x-y)^2+(x+y)(x-y)]÷2x的值
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
若x y满足x^2+y^2-2x+4y=0求x-2y的最大值
若x^2+y^2-10x-6y+34=0,求(x-y)/(x+y)的值
已知:4x^2+y^2-4x-6y+10=0,求y/x-x/y的值