lg2(lg5-lg2)-lg5(lg5+3lg2)等于
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lg2(lg5-lg2)-lg5(lg5+3lg2)等于lg2(lg5-lg2)-lg5(lg5+3lg2)等于lg2(lg5-lg2)-lg5(lg5+3lg2)等于lg2(lg5-lg2)-lg5
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
lg2(lg5-lg2)-lg5(lg5+3lg2)
=lg2lg5-(lg2)^2-(lg5)^2-3lg5lg2
=-[(lg2)^2+2lg2lg5+(lg5)^2]
=-(lg2+lg5)^2
=-[lg(2*5)]^2
=-1
lg5+lg5*lg2+lg2*lg2
lg2*lg2+lg5-lg2=?
lg2(1+lg5)+(lg5)^2
计算：(lg5)^2 +lg2 *lg5
(lg5)^2+lg5.lg2=
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
化简lg5的平方+lg5×lg2+lg2
(lg2)^3+(lg5)^3+3*lg2*lg5
(lg2)³+(lg5)³+3lg2×lg5
lg2*lg50+lg5*lg20-2lg5*lg2
2lg2（lg2+lg5)+2lg5得数
（lg5）²+lg2×lg5+lg2
(lg2)^2+lg2*lg5+(lg5)^2=
数学题(lg2)平方+lg5*lg2+lg5
(lg5)平方+2*lg5*lg2+(lg2)平方
lg5(1-lg5)+2lg5根号2+lg2(1-lg5)
lg2*lg2+lg20*lg5=?
为什么(lg5+lg2)*(lg5-lg2)=lg5-1g2