计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-2103i)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/02 17:55:27
计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-2103i)计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-

计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-2103i)
计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-2103i)

计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-2103i)
原式=[(1-2)+(3-4)+…+(2101-2102)]+[(-2+3)+(-4+5)+…+(-2102+2103)]i
=-2102/2+(2102/2)i
=-1051+1051i