[(2x+y)^2-(2x+y)(-y+2x)]/2y-二分之一y,其中x=1,y=2
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[(2x+y)^2-(2x+y)(-y+2x)]/2y-二分之一y,其中x=1,y=2[(2x+y)^2-(2x+y)(-y+2x)]/2y-二分之一y,其中x=1,y=2[(2x+y)^2-(2x+
[(2x+y)^2-(2x+y)(-y+2x)]/2y-二分之一y,其中x=1,y=2
[(2x+y)^2-(2x+y)(-y+2x)]/2y-二分之一y,其中x=1,y=2
[(2x+y)^2-(2x+y)(-y+2x)]/2y-二分之一y,其中x=1,y=2
:[(2x+y)^2-(2x+y)(-y+2x)]/2y-二分之一y
=(2x+y)(2x+y+y-2x)/2y-y/2
=2x+y-y/2
=2x +y/2
当 x=1,y=2时
原式=2+1=3
带入数字[4*4-4*0]/4-1=3
如果其中(-y+2x)你没写反的话
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原式=3
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