-1\2x^2+xy-1\2y^2 (因式分解)
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-1\2x^2+xy-1\2y^2(因式分解)-1\2x^2+xy-1\2y^2(因式分解)-1\2x^2+xy-1\2y^2(因式分解)-1\2x^2+xy-1\2y^2=-1/2(x²-
-1\2x^2+xy-1\2y^2 (因式分解)
-1\2x^2+xy-1\2y^2 (因式分解)
-1\2x^2+xy-1\2y^2 (因式分解)
-1\2x^2+xy-1\2y^2
=-1/2(x²-2xy+y²)
=-1/2(x-y)²
-1\2x^2+xy-1\2y^2
=-1/2(x^2-2xy+y^2)
=-1/2(x-y)^2
分解因试(x-1)²-2(x-1)+1 x³y-2x²y²+xy³
.(x+y-2)(x+y-2xy)+(xy-1)^2
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
求三道因试分解的题X³Y-2X²Y²+XY³ X²-4(X-1) 4X²-8X+4
计算3xy[2xy-x(y-2)+x-1]
{(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)
6x^2-xy-2y^2-4x+5y-2因试分解
分解因试..X平方-2XY-8Y平方-X-14Y-6
1.(xy-1)^2-(x+y-2xy)(2-x-y)2.(x+y)(x+y+2xy)+(xy-1)(xy+1)
xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解
(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
(-3分之1xy)的平方×[xy(2x-y)-2x(xy-y的平方)]
已知x+y=1,xy=-2,则x²y+xy²-2xy
因式分解(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)
1-2/x+y=xy,4y+6x=xy.求xy的解?
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)