f(α)=sin(π-α)*cos(2π-α)/sin(3π/2-α)tanα,则f(-10π/3)等于a.1/2 b.-1/2 c.(2√3)/3 d.-(2√3)/3

设f(α)=[2sin(π+α)cos(π-α)-cos(π+α)]/[(1+sin^2α+sin(π-α)-cos^2(π-α),求f(-23π/6)的值 设f(α)=[2sin(π+α)cos(π-α)-cos(π+α)]/[(1+sin^2α+sin(π-α)-cos^2(π-α),求f(-23π/6)的值 若f（sinα+cosα）=sinαcosα,则f（cosπ/6)等于..麻烦讲清楚过程,辛苦各位了. 化简 f(α)=sin(π/2-α)cos(π/2+α) 这整个除以sin(π+α) 已知f(α)= sin(π-α)cos(2π-α)cos(-α+3/2π)/cos(π/2-α)sin(-π-α) (1)化简f(α) (2)若α...已知f(α)= sin(π-α)cos(2π-α)cos(-α+3/2π)/cos(π/2-α)sin(-π-α)(1)化简f(α)(2)若α为第二象限的角,且cos(α-3/2π)=1/5,求f(α)的值 设f(sinα+cosα)=sinα·cosα,则f[sin(π/6)]=_______?要有过程 高中数学三角函数化简题已知 fα=sin(π-α)cos(2π-α)cos(-α+3/2π)/cos(π/2-α)sin（-π-α）已知fα=sin(π-α)cos(2π-α)cos(-α+3/2π)/cos(π/2-α)sin（-π-α）化简若α第三象限,且cos(α-3/2π)=1/5,求fα若α=-31/3π,求f f(α)=4sinαcos(π/2-α)+4sin(π-α)cos(-α)-1最大值快点 十万火急下 cosα*cosβ=1,cos(α+β）等于sinαsinβ+cosαcosβ=0,则sinαcosα+sinβcosβ的值为已知tan（π/4+α）=2,求1/（2sinαcosα+（cosα）^2)的值求函数f(x)=2+2sinxcosx+sinx+cosx的最大值和最小值 π〈α〈2π且f(α）={√2-2 cosα}/{（1-sinα-cosα）（cosα/2+sinα/2）}请化简f（α）步骤尽量详细点 已知α∈(0,π/2),f(α)=1/sinα+8/cosα,则f(α)最小值为 f(x)=(2-sinα)/cosα的导数 cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的? 已知f(α)=sin(π-α)cos(2π-α)tan(-α+3π/2)/cos(-π-α)则f（-13π/3）的值是 已知f(α)=(tan(π-α)*cos(2π-α)*sin(二分之π+α))/(cos(-α-π)) (1)化简f(α） 已知f(α)=(sin(Π／2-α)cos(2Π-α)tan(-α+3Π))／(tan(Π+α)sin(Π／2＋α)),化简f(α) sin(α-π)=2cos（α-2π）求cos平方α-sin平方αcosα .若f(x)=sinα－cosx,则f′(α)等于 A.sinα B.cosα C.sinα+cosα D.2sinα