设f(α)=[2sin(π+α)cos(π-α)-cos(π+α)]/[(1+sin^2α+sin(π-α)-cos^2(π-α),求f(-23π/6)的值

设f(α)=[2sin(π+α)cos(π-α)-cos(π+α)]/[(1+sin^2α+sin(π-α)-cos^2(π-α),求f(-23π/6)的值 设f(α)=[2sin(π+α)cos(π-α)-cos(π+α)]/[(1+sin^2α+sin(π-α)-cos^2(π-α),求f(-23π/6)的值 设f(sinα+cosα)=sinα·cosα,则f[sin(π/6)]=_______?要有过程 设f(sinα+cosα)=sinα*cosα 则f(0)+f(1)的值~! 设f(x)=2cos三次方α+sin²(2π-α)+cos(2π-α)-3/2+2cos²(π+α)+cos(-α),求f(π/3)详细过程 设f(α)=2sinαcosα+cosα/1+sin²α+cos(3π/2+α)-sin²(π/2+α) （1+2sinα不等于0）则f(1度）×f(2度）×（3度）‘’‘’‘’‘’‘’‘’‘’‘’‘f(89度）的值为 设tan(π+α)=2,则sin(α-π)+cos(π-α)/sin(π+α)-cos(π+α)= 设α,β,γ∈(0,π/2),且sinβ+sinγ=sinα,cosα+cosγ=cosβ,则β-α= 设tanα=2,计算sinα+cosα／sinα-cosα 设tanα=2,计算sinα+cosα/sinα-cosα急 设sinα-cosα=1/2,求sinα*cosα= 设f(sinα+cosα)=sin2α,则f(1/5)的值为 设f(sinα+cosα)=sin2α,则f(1/5)的值为 设f(α)=(2sinαcosα+cosα)/[(1+sin^2α+cos(3/2π+α)-sin^2(π/2+α)](1+sinα≠0)（1）化简f（α）（2）求f（1°）+f（2°）+f（3°）+……+f（89°）不好意思，第二问是求f（1°）*f（2°）*f（3°）*……*f（89°） 设f(α)=[2sin(π+α)cos(π-α)-cos(π+α)]/[(1+sin^2α+sin(π-α)-cos^2(π-α)1.若α=-17/6π,求f(α)的值2.若α是锐角,则sin(α-3/2π)=3/5,求f(α)的值 设f(cos^2x)=sin^2x,则f'(π/4)等于, 设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π＋α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2（-sinα)(-cosα）+cosα/[1+sin² 设α∈（0,π/2）,则cosα,sin(cosα),cos(sinα)的大小关系为什么?