4x^4-4√2x^3-4x^2+x√2x+1=0算了好久不回算...哦不对 是4x^4-4√2x^3-4x^2+2√2x+1=0

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4x^4-4√2x^3-4x^2+x√2x+1=0算了好久不回算...哦不对是4x^4-4√2x^3-4x^2+2√2x+1=04x^4-4√2x^3-4x^2+x√2x+1=0算了好久不回算...哦

4x^4-4√2x^3-4x^2+x√2x+1=0算了好久不回算...哦不对 是4x^4-4√2x^3-4x^2+2√2x+1=0
4x^4-4√2x^3-4x^2+x√2x+1=0
算了好久不回算...
哦不对

4x^4-4√2x^3-4x^2+2√2x+1=0

4x^4-4√2x^3-4x^2+x√2x+1=0算了好久不回算...哦不对 是4x^4-4√2x^3-4x^2+2√2x+1=0
左式= 2 (2x^2-1) * (x^2 - 根号2 * x -1/2)=0
所以2x^2 -1=0 或x^2 - 根号2 * x -1/2=0
解得x= + 或 - (根号2)/2
或x= (根号2)/2 + 或 - 1

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