(y/3+y/4)÷2=y/x 请问怎样消去y 得到1/3-1/x=1/x-1/4
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/18 19:54:02
(y/3+y/4)÷2=y/x请问怎样消去y得到1/3-1/x=1/x-1/4(y/3+y/4)÷2=y/x请问怎样消去y得到1/3-1/x=1/x-1/4(y/3+y/4)÷2=y/x请问怎样消去y
(y/3+y/4)÷2=y/x 请问怎样消去y 得到1/3-1/x=1/x-1/4
(y/3+y/4)÷2=y/x 请问怎样消去y 得到1/3-1/x=1/x-1/4
(y/3+y/4)÷2=y/x 请问怎样消去y 得到1/3-1/x=1/x-1/4
(y/3+y/4)÷2=y/x
(y/3+y/4)=2y/x 两边同乘以2
(1/3+1/4)=2/x 两边同除以Y,Y不等于0
1/3-1/x+1/4=1/x 两边同减去1/X
1/3-1/x=1/x-1/4 两边同减去1/4
两边通除以Y。然后两边乘以2
(y/3+y/4)÷2=y/x 请问怎样消去y 得到1/3-1/x=1/x-1/4
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
[(x+y)(x-y)-(x-y)²+2y(x-y)]÷4y
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
请问如何化简(4x-y)/x^2y^2 - (x+y)/xy^3
请问算到4x/y=3y/x后怎么算出x,y,
请问 0=-5x+y-1 与 1=4x-3y+2 x*y的值是多少
4x-3y/x-2y÷6y-8x/y-2x
2(x+y)-3(x-y)=3 ,4(x+y)+3(x-y)=15
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)