y=2sin(π/6-2x)(π/3≤x≤π) 值域
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y=2sin(π/6-2x)(π/3≤x≤π)值域y=2sin(π/6-2x)(π/3≤x≤π)值域y=2sin(π/6-2x)(π/3≤x≤π)值域先变形:f(x)=-2sin(2x-π/6)所以当
y=2sin(π/6-2x)(π/3≤x≤π) 值域
y=2sin(π/6-2x)(π/3≤x≤π) 值域
y=2sin(π/6-2x)(π/3≤x≤π) 值域
先变形:f(x)= -2sin(2x-π/6)
所以当:2kπ+π/2≤2x-π/6≤2kπ+3π/2即:kπ+π/3≤x≤kπ+5π/6时,
f(x)是增函数;
所以f(x)的增区间为:[kπ+π/3,kπ+5π/6],k∈Z
那么值域就是(0,2]
值域为【0,1】
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