16(x-3)(x-3)+8(x-30+1=0

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16(x-3)(x-3)+8(x-30+1=016(x-3)(x-3)+8(x-30+1=016(x-3)(x-3)+8(x-30+1=0[4(x-3)+1]^2=0x-3=-1/4x=11/44(x

16(x-3)(x-3)+8(x-30+1=0
16(x-3)(x-3)+8(x-30+1=0

16(x-3)(x-3)+8(x-30+1=0
[4(x-3)+1]^2=0
x-3=-1/4
x=11/4

4(x-3)2=0
4(x-3)=0
x-3=0
x=3

疑为16(x-3)(x-3)+8(x-3)+1=0
[4(x-3)+1]^2=0
4(x-3)+1=0
4x=11
x=11/4

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