若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
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若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=若1/x+2/y+z/3=4,3
若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
若1/x+2/y+z/3=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
题目里是3/z吧.
若1/x+2/y+3/z=4,3/x+2/y+1/z=6
则1/x+2/y+z/3 + 3/x+2/y+1/z
=4/x+4/y+4/z
=4(1/x+1/y+1/z)
= 4 + 6
则
1/x+1/y+1/z = 10/4 = 5/2
那个..第一个式子是1/x+2/y+3/z=4么??如果是这样..那么
1/x+2/y+3/z=4,3/x+2/y+1/z=6
把2个式子相加
4/x+4/y+4/z=10
所以1/x+1/y+1/z=5/2
1/x+2/y+z/3=4这一式应为1/x+2/y+3/z=4,因此两式相加得4/x+4/y+4/z=10,1/x+1/y+1/z= 5/2
题目是不是错了,应该是这样的吧1/x+2/y+3/z=4,3/x+2/y+1/z=6.则1/x+1/y+1/z=
设 1/x+2/y+3/z=4 1式
3/x+2/y+1/z=6 2式
1式+2式得 4/x+4/y+4/z=10
4*(1/x+1/y+1/z)=10
1/x+1/y+1/z=10/4=2.5
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