帮忙用洛必达法则解答!我做不对!

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帮忙用洛必达法则解答!我做不对!帮忙用洛必达法则解答!我做不对!帮忙用洛必达法则解答!我做不对!原式=lim(x->0)3x²ln(1+2sinx³)/[3(∫(0,x)ln(1+

帮忙用洛必达法则解答!我做不对!
帮忙用洛必达法则解答!我做不对!

帮忙用洛必达法则解答!我做不对!
原式=lim(x->0)3x²ln(1+2sinx³)/[3(∫(0,x)ln(1+2sint)dt)²×ln(1+2sinx)]
=lim(x->0)x²ln(1+2sinx³)/[(∫(0,x)ln(1+2sint)dt)²×ln(1+2sinx)]
=lim(x->0)x²(2sinx³)/[(∫(0,x)ln(1+2sint)dt)²×(2sinx)]
=lim(x->0)x²(x³)/[(∫(0,x)ln(1+2sint)dt)²×(x)]
=lim(x->0)(x^4)/[(∫(0,x)ln(1+2sint)dt)²]
=lim(x->0)(4x³)/2[(∫(0,x)ln(1+2sint)dt)]ln(1+2sinx)
=lim(x->0)(x³)/[(∫(0,x)ln(1+2sint)dt)](sinx)
=lim(x->0)(x³)/[(∫(0,x)ln(1+2sint)dt)]x
=lim(x->0)(x²)/[(∫(0,x)ln(1+2sint)dt)]
=lim(x->0)(2x)/(ln(1+2sinx))
=lim(x->0)(2x)/(2sinx)
=lim(x->0)(2x)/(2x)
=1