25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程
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25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程原
25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程
25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程
25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程
原式=1/4*m/2+【4/5*5/4-1】*m/2
=1/8m
=0.4x(m/2)+(0.8x1.4-1)x(m/2)=(0.4+1.12-1)x(m/2)=0.52x(m/2)=0.26x
25%x(m/2)+[0.8(1+25%)-1]x(m/2)的过程
几道二元一次方程1.2002x^2+2003x+1=02.(m-2)x^2-(m+3)x-2m-1=03.(m^2-25)x^2-2m^2 x+m^2=0
因式分解30x^(3m+1)-(25x^3m)+(5x^m)能不能继续分解
m x平方-2x-m+1
因式分解(m-1)x-(x^2-m)
英语翻译for k = 1:12N = X(n,:) + X(s,:) + X(:,e) + X(:,w) + X(n,e) + X(n,w) + X(s,e) + X(s,w)RAND = rand(m)X = X | (N.*RAND>0.99)endm = 50;X = zeros(m,m);X(25,25) = 1;n = [m 1:m-1];e = [2:m 1];s = [2:m 1];w = [m 1:m-1];
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(1)9m^2-15m+4分之25 (2)4分之1x+x^3-x^2
x^2-(2m+1)x+m^2+m
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