log2(a)=log3(b)=log5(c)

log2(a)=log3(b)=log5(c) log2[log3[log5 125]]=?log2[log3[log5 125]]=? log5[log2(log9/log3)]=? 设a=log3²,b=log5²,c=log2³,比较大小 一道高一数学题7设log2=a,log3=b,则log5^12=? log5怎么表示（已知log2=a,log3=b） 已知log2=a,log3=b,用a、b表示log5 72 (急~）1.已知log2=a,log3=b,用a、b表示log5 722.已知x=log2 5,求2^x+4^-x 1、计算log5^35+2log1/2^根号2-log5^1/50-log5^14 2、已知log3^7=a,log2^3=b,求log21^28 2log5 10+log5 0.25= 2log5 25-3log2 64= log2(log2 16)= 已知lg2=a,lg3=b,求log3 4,log2 12 若log2(x)=log3(y)=log5(z) log5[log3(log2^x)]=1,x= log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= log3 25×log2 27×log5 2^-3=_____ log5［log2（log3 9）］= log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12= 已知a=log3(4),4^b=3,则log5(a)+log5(b)=? log4(log5 a)=log3(log5 b)=1,求a/b.