化简:sin^4 x-sin^2 x+cos^2 x
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化简:sin^4x-sin^2x+cos^2x化简:sin^4x-sin^2x+cos^2x化简:sin^4x-sin^2x+cos^2xsin^4x-sin^2x+cos^2x=sin^2x(sin
化简:sin^4 x-sin^2 x+cos^2 x
化简:sin^4 x-sin^2 x+cos^2 x
化简:sin^4 x-sin^2 x+cos^2 x
sin^4 x-sin^2 x+cos^2 x=sin^2x(sin^2x-1)+cos^2x=-sin^2xcos^2x+cos^2x=cos^2x(-sin^2x+1)=cos^4x
化简sin^4x-sin^2x+cos^2x
化简:sin^4 x-sin^2 x+cos^2 x
化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
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傅里叶级数作图f(x)=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si
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化简【完整步骤!】1.(sin^4x-sin^2x)/secx2.sin^4x-cos^4x【这道题的正确答案是sin^2x-cos^2x】
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