若x^2+2x+1+y^2-8x+16=0,求x分之y的值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 19:42:49
若x^2+2x+1+y^2-8x+16=0,求x分之y的值若x^2+2x+1+y^2-8x+16=0,求x分之y的值若x^2+2x+1+y^2-8x+16=0,求x分之y的值x^2+2x+1+y^2-
若x^2+2x+1+y^2-8x+16=0,求x分之y的值
若x^2+2x+1+y^2-8x+16=0,求x分之y的值
若x^2+2x+1+y^2-8x+16=0,求x分之y的值
x^2+2x+1+y^2-8x+16=0
(x+1)²+(y-4)²=0
﹛x+1=0
y-4=0
∴x=-1,y=4
x分之y=-4
若x-y=1 化简(x+y)(x^2+y^2)(x^4+y^4)(x^8+y^8)(x^16+y^16)
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若x*x+y*y=x+y-1/2,求x,y的值如题
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
若x+y=1,x不等于0则x+(2xy+y^2)/x/(x+y)/x=
3分之2(x-y)-4分之x+y=-1 8(x+y)-4(2x-y)=16
若√x-1-√1-x=(x+y)²先化简再求值:(1/2x)-(1/x+y)[x²-y²+(x+y/2x]
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
若x^2+2x+1+y^2-8x+16=0,求x分之y的值
[(2x-y)^2-y(y-4x)-8x]其中x=-1/2
16-8(x-y)+(x-y)2
x^+2x+1+y^2-8y+16=0求y/x
若变量x,y满足约束条件{x>=-1;y>=x;3x+2y
9y=3x-(x-1),4(x+y)-(2x+4)=8y
[(2x+y)²-y(y+4x)-8x】/4x,其中x=-1,y=2005 急
已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2)
已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2)