y=-[(4/3)x^2]+8x (0
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y=-[(4/3)x^2]+8x(0y=-[(4/3)x^2]+8x(0y=-[(4/3)x^2]+8x(0y=-[(4/3)x^2]+8x=y=-(4/3)(x-3)^2+12所以这个二次函数的对称
y=-[(4/3)x^2]+8x (0 y=-[(4/3)x^2]+8x (0 y = -[(4/3)x^2]+8x
y=-[(4/3)x^2]+8x (0
y=-[(4/3)x^2]+8x=y=-(4/3)(x-3)^2+12
所以这个二次函数的对称轴为x=3,当0
= -(4/3)(x-3)^2 +12
当x-3=0,即x=3时
Y有最大值。
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