解log2^x

解log2^x 解不等式|log2(x)+x| 解不等式：|log2（x-1）|+log2（5-x） 解方程：log2(x)+log2(x-8)=7 解方程log2(2-x)=log2(x-1)+1 log2(x2-x-2)>log2(2x-2)解不等式 解不等式log2(4x+8)>log2(2x+1) 解不等式2log2 (x-4)< log2 (x-2) 解2log2^(x-5)=log2^(x-1)+1 谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1) 解方程：log2(x+4)+log2(x-1)=1+log2(x+8) 解方程log2(x+14)-log2(x+6)=3-log2(x+2) log2(x+1)+log2x=log2（6）解方程 log2^(x^log2^x)=? 解不等式：log2(x^2-x-2) 解不等式log2(4x-x^2) 已知函数f(x)=log2^ ( x/4 ) ×log2^ (2x) (1)解不等式f(x)>0;(2)当x∈【1,4】时,求f(x)的值域f（x）=log2（2x）×log2（x／4）＝[（log2 2）+(log2 x)] ×[(log2 x) -(log2 4)]=[1+(log2 x)] ×[(log2 x) -2]=(log2 x)² - (log2 x) -2 解不等式Log2(4+3x-x^2)>log2(4x-2)那个log2的2是底数