若x-3y+4z=1,2x+y-2z=2,化简x^2-2xy-3y^2+2xz+10yz-8z^2的结果
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若x-3y+4z=1,2x+y-2z=2,化简x^2-2xy-3y^2+2xz+10yz-8z^2的结果若x-3y+4z=1,2x+y-2z=2,化简x^2-2xy-3y^2+2xz+10yz-8z^
若x-3y+4z=1,2x+y-2z=2,化简x^2-2xy-3y^2+2xz+10yz-8z^2的结果
若x-3y+4z=1,2x+y-2z=2,化简x^2-2xy-3y^2+2xz+10yz-8z^2的结果
若x-3y+4z=1,2x+y-2z=2,化简x^2-2xy-3y^2+2xz+10yz-8z^2的结果
(x-3y)(x+y)+2xz+10yz-8z²
十字相乘
x-3y 4z
×
x+y -2z
所以原式=(x-3y+4z)(x+y-2z)=2
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x+y+z=6 x+2y+3z=14 y+1=z
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x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
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x+y+z=2 4x+2y+z=4 2x+3y+z=1
4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1
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