函数y=2cos(2x+π/3)(x∈[-π,0])的单调增区间

函数y=cos(3π/2-x)/cos(3π-x)最小正周期是 函数y=cos(3π/2-x)/cos(3π-x)最小正周期是： 函数y=2cos(x-π/3)(π/6 函数y=3cos(2x-π/3)最小值 求函数y=cos(x-π/3),x∈[-π/2,π/2]的值域, 函数y=cos(x+π/3)的值域(其中x∈[-π/2,π/3]) 函数y=cos(x-π/8)(x∈[π/6,2π/3]的最小值. 函数y=cos(x-π/6)(x∈【π/6,2π/3】)的最小值 函数y=cos(x-π/6)(x∈[π/6,2π/3]的最小值. 函数y=3cos(-2x+π/4)x∈[-π,π]的减区间 函数y=cos(x/2-π/3),x∈【0,2π】的值域是 函数y=cos(x-π/6)(x∈[0,2/3π])的最大值是? 求函数y=cos^2x+3cos x+2,x属于【0,π/2)的值域? 函数y=sin(2x+α)cos(x+α)-cos(2x+α)sin(x+α)在x=π/3处的导函数为 函数y=2sin( π/3 -x)-cos( π/6 +x)(x∈R)的最小值等于 函数y=cosπ/2x×cosπ/2(x-1)的最小正周期 函数y=cosπ/2x×cosπ/2(x-1)的最小正周期 化简函数y=cos^2(x+7π/12)-cos^2(x+π/12),