[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013先化简。在求值

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[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012y=2013先化简。在求值[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012y=2013先化简。在求值

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013先化简。在求值
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
先化简。在求值

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013先化简。在求值
先一个一个的展开括号项,再同项合并就行了啊
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x
=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x
=[xx-xy-xy+yy+xx-xy+xy-yy]÷2x
=(2xx-2xy)÷2x
=2x(x-y) ÷2x
=x-y
代入数值即可.

先去除小括号，再去大括号，就可以了

先简化代数式。前两项合并为（x-y）（x-y）与后项相加为2x（x-y），除以2x等于x-y.答案等于-1

我觉得这样更好：
原式=[(x-y)(x-y)+(x+y)(x-y)]÷2x
=(x-y+x+y)(x-y)÷2x
=2x(x-y)÷2x
=x-y
所以原式=2012-2013=-1

{(x,y) |x|+|y| x>y?x:y x^/y-x-y^/y-x化简. 化简x(y-x)-y(x-y) 行列式计算 x y x+y y x+y x x+y x y|x y x+y ||y x+y x ||x+y x y | y/(x+y)-x/(x-y) x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 x y x+yy x+y xx+y x y (3x-y)(3y+x)-(x-y)(x+y) 化简x/y(x+y)-y/x(x+y) 化简 x / y(x+y) - y / x(x+y) = 化简:(x+ y)(x-y) +(x+ y) +(x-y) x+y (x+y) |x+y| x y x+yy x+y xx+y x y 化简y(x+y)+(x+y)(x-y)-x^2 |x|+|y|