12x+32y=1 27x+12y=1 这个方程组怎样解?

x.y都是自然数,且x(x-u)-y(y-x)+12,求x.y得值快1且x(x-y)-y(y-x)=12 [(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值. 解方程组 2x-y=5 2y/x-x/y=12x-y=52y/x-x/y=1 已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2) 已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2) 4/X+1/Y=2,XY=-1,求代数式4Y-X/X-2Y/（x+2y-12Y²/x-2y)的值 解方程组 （x+y）（x+y-1）=56 （x-y）（x-y-1）=12 (x+y)(x+y+1)=56,(x-y)(x-y+1)=12如何解这个方程组? 解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12) 解方程组{2(x-y)/3 - x+y/4=-1 6(x+y)-41(x-y)=12 解方程：（x+3)(y-2)=(x-3)(y+10) (x-1)(y+3)=(x+2)(y+12) 4x³y+12x²y²+9x y³/4x³-9x y²,其中x=1,y=1. X+2Y= -12X+Y+Z= 1-X+Y-Z= -1 x+y/10+x/15=1x+y/12+y/15=1 解方程组x-4y=-1x-4y=-12x+y=16 y'/y=1/x 4(x+2)=1-5y 4(x+y)-3(x-y)=12 已知x:y=3:1,且x+y=12,求x-y的值.